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x 2 1 )( x 3 )= 0
x 2 1 )( x 3 )= 0
x 2 2x 1 )( x 3 )= 0
x 2 3 1 x 3 0 solve
4 x 2 x 1 3 0
x 2 1 )( x 2 4x 3 )= 0
x 2 y 1 )( x 3 y 0
x ^ 2 - 3 + 1 x + 3 = 0
5 x 1 )+ 2 x 3 )+ 6 0
x 2 64 then x 1 3 x 0